[Code of Federal Regulations]
[Title 27, Volume 1]
[Revised as of April 1, 2007]
From the U.S. Government Printing Office via GPO Access
[CITE: 27CFR30]

[Page 860]
 
            TITLE 27--ALCOHOL, TOBACCO PRODUCTS AND FIREARMS
 
 CHAPTER I--ALCOHOL AND TOBACCO TAX AND TRADE BUREAU, DEPARTMENT OF THE 
                                TREASURY
 
PART 30_GAUGING MANUAL--Table of Contents
 
                       Subpart E_Prescribed Tables
 
Sec.  30.64  Table 4, showing the fractional part of a gallon per pound at 

each percent and each tenth percent of proof of spirituous liquor.

    This table provides a method for use in ascertaining the wine gallon 
(at 60 degrees Fahrenheit) and/or proof gallon contents of containers of 
spirits by multiplying the net weight of the spirits by the fractional 
part of a gallon per pound shown in the table for spirits of the same 
proof. Fractional gallons beyond the first decimal will be dropped if 
less than 0.05 or will be added as 0.1 if 0.05 or more.

    Example. It is desired to ascertain the wine gallons and proof 
gallons of a tank of 190 proof spirits weighing 81,000 pounds.

81,000x0.14718=11,921.58=11,921.6 wine gallons.
81,000x0.27964=22,650.84=22,650.8 proof gallons.


This table may also be used for ascertaining the quantity of water 
required to reduce to a given proof. To do this, divide the proof 
gallons of spirits to be reduced by the fractional part of a proof 
gallon per pound of spirits at the proof to which the spirits are to be 
reduced, and subtract from the quotient the net weight of the spirits 
before reduction. The remainder will be the pounds of water needed to 
reduce the spirits to the desired proof.

    Example. It is desired to ascertain the quantity of water needed to 
reduce 1,000 pounds of 200 proof spirits, 302.58 proof gallons, to 190 
proof:

302.58 divided by 0.27964 equals 1,082.03 pounds, weight of spirits 
after reduction.
1.082.03 minus 1,000 equals 82.03 pounds, weight of water required to 
reduce to desired proof.


The slight variation between this table and Tables 2, 3, and 5 on some 
calculations is due to the dropping or adding of fractions beyond the 
first decimal in those tables. This table may also be used to determine 
the wine gallons (at 60 degrees Fahrenheit) of distilled spirits 
containing dissolved solids from the total weight of the liquid and its 
apparent proof (hydrometer indication, corrected to 60 degrees 
Fahrenheit). The proof gallons may then be found by multiplying the wine 
gallons by the true proof.

    Example. 5,350 pounds of blended whisky containing added solids

Temperature [deg]F.............................................75.0[deg]
Hydrometer reading.............................................92.0[deg]
Apparent proof.................................................85.5[deg]
Obscuration.....................................................0.5[deg]
True proof.....................................................86.0[deg]

5,350.0 lbs.x0.12676 (W.G. per pound factor for apparent proof of 
85.5[deg])=678.2 wine gallons
678.2 W.G.x0.86=583.3 proof gallons

(Sec. 201, Pub. L. 85-859, 72 Stat. 1358, as amended 1362, as amended 
(26 U.S.C. 5204, 5211))